2CH\(_3\)COOH + Zn \(\rightarrow\) ? The product of this reaction is
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2CH\(_3\)COOH + Zn \(\rightarrow\) ? The product of this reaction is
- A)(CH\(_3\)COO)\(_2\)Zn + Zn
- B)CH\(_3\)COOCH\(_3\) + Zn
- C)(CH\(_3\)COO)\(_2\)Zn + H\(_2\)
- D)CH\(_3\)COOH + CH\(_4\)
Correct Answer: C)(CH\(_3\)COO)\(_2\)Zn + H\(_2\)
Explanation
The given reaction is:
\(2CH_3COOH + Zn \rightarrow ?\)
In this reaction, we have acetic acid (CH\(_3\)COOH) reacting with zinc (Zn). This is an example of a metal reacting with an acid, which typically results in the formation of a salt and hydrogen gas (H\(_2\)).
In this case, the salt formed is zinc acetate ((CH\(_3\)COO)\(_2\)Zn), and the other product is hydrogen gas (H\(_2\)). So, the balanced equation for this reaction is:
\(2CH_3COOH + Zn \rightarrow (CH_3COO)_2Zn + H_2\)Therefore, the correct answer isOption C: (CH\(_3\)COO)\(_2\)Zn + H\(_2\).
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