The reduction potential of two electrodes are \(X^{2+} + 2e^- \rightarrow X, E^0 = 0.042V\)
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The reduction potential of two electrodes are
\(X^{2+} + 2e^- \rightarrow X, E^0 = 0.042V\)
\(Y^+ + e^- \rightarrow Y, E^0 = 0.012V\)
Calculate the free energy change for the cell that is made up of the electrodes [F = 96500 Coulomb mol?1]
- A) 4.20kJ
- B) 5.79kJ
- C) 6.86kJ
- D) 10.55kJ
Correct Answer: B) 5.79kJ
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