Uranium-235 explodes when bombarded with a slow moving neutron according to the equation below:\(^{235}_{92}U +...

Explanation

The given nuclear reaction is:

\(^{235}_{92}U + ^1_0n \rightarrow ^{94}_{36}Kr + Ba + 3^1_0n\)

When a slow-moving neutron bombards Uranium-235, it undergoes nuclear fission, producing Krypton-94 and Barium (Ba) as well as releasing three more neutrons. To find the atomic number and mass of Barium, we need to apply the law of conservation of mass and atomic number in nuclear reactions.

The law of conservation of mass states that the sum of the masses on the left side of the equation must be equal to the sum of the masses on the right side. Similarly, the law of conservation of atomic number states that the sum of the atomic numbers on the left side of the equation must be equal to the sum of the atomic numbers on the right side.

Let's first find the atomic number of Barium:

On the left side, we have Uranium with an atomic number of 92 and a neutron with an atomic number of 0, giving a total atomic number of 92. On the right side, we have Krypton with an atomic number of 36, and Barium with an unknown atomic number. So, we can write:

\(92 = 36 + Z_{Ba}\)

Solving for the atomic number of Barium, we get:

\(Z_{Ba} = 92 - 36 = 56\)

Now let's find the mass of Barium:

On the left side, we have Uranium with a mass of 235 and a neutron with a mass of 1, giving a total mass of 236. On the right side, we have Krypton with a mass of 94, Barium with an unknown mass, and three neutrons each with a mass of 1, giving a total mass of \(94 + A_{Ba} + 3\). So, we can write:

\(236 = 94 + A_{Ba} + 3\)

Solving for the mass of Barium, we get:

\(A_{Ba} = 236 - 94 - 3 = 139\)

Therefore, the atomic number and mass of Barium are 56 and 139, respectively. The correct answer isOption C: 56 and 139.