Find the coordinates of the point in the curve y = 3x\(^2\) - 2x -
FURTHER MATHEMATICS
WAEC 2019
Find the coordinates of the point in the curve y = 3x\(^2\) - 2x - 5 where the tangent is parallel to the line y = - 5 = 8x
- A. \(\begin{pmatrix} - \frac{5}{3} &, 0 \end {pmatrix}\)
- B. \(\begin{pmatrix} 0, & - \frac{5}{3} \end {pmatrix}\)
- C. \(\begin{pmatrix} 0, & \frac{5}{3} \end {pmatrix}\)
- D. \(\begin{pmatrix} \frac{5}{3} &, 0 \end {pmatrix}\)
Correct Answer: D. \(\begin{pmatrix} \frac{5}{3} &, 0 \end {pmatrix}\)
Explanation
y = 8x + 5
m = 8
y = 3x\(^2\) - 2x - 5
\(\frac{dy}{dx}\) = 6x - 2x - 5
\(\frac{6x}{6} = \frac{10}{6}\)
x = \(\frac{5}{3}\)
y = 0
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