The polynomial \(2x^{3} + x^{2} - 3x + p\) has a remainder of 20 when
FURTHER MATHEMATICS
WAEC 2008
The polynomial \(2x^{3} + x^{2} - 3x + p\) has a remainder of 20 when divided by (x - 2). Find the value of constant p.
- A. 8
- B. 6
- C. -6
- D. -8
Correct Answer: B. 6
Explanation
Remainder for f(2) = 20.
\(f(2) = 2(2^{3}) + 2^{2} - 3(2) + p = 20\)
\(16 + 4 - 6 + p = 20\)
\(14 + p = 20\)
\(p = 6\)
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