If \(f(x) = 2x^{2} - 3x - 1\), find the value of x for which
FURTHER MATHEMATICS
WAEC 2008
If \(f(x) = 2x^{2} - 3x - 1\), find the value of x for which f(x) is minimum.
- A. \(\frac{3}{2}\)
- B. \(\frac{4}{3}\)
- C. \(\frac{3}{4}\)
- D. \(\frac{2}{3}\)
Correct Answer: C. \(\frac{3}{4}\)
Explanation
\(y = 2x^{2} - 3x - 1\)
\(\frac{\mathrm d y}{\mathrm d x} = 4x - 3 = 0\) (At turning point)
\(4x = 3 \implies x = \frac{3}{4}\)
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