The probability of producing an heterozygote progeny in a cross between two heterozygote individuals of...

Explanation

In this question, we are asked to determine the probability of producing a heterozygote progeny in a cross between two heterozygote individuals of pea plant. To understand this, we need to first understand the concept of heterozygotes and the Punnett square. Heterozygote individuals have two different alleles for a specific trait (e.g., Tt, where T represents the dominant trait and t represents the recessive trait). In pea plants, let's assume that the tall trait (T) is dominant over the short trait (t). So, a heterozygote pea plant would have a genotype of Tt. To find the probability of producing a heterozygote offspring, we can use the Punnett square. The Punnett square is a tool that helps us visualize the possible combinations of alleles in the offspring. In this case, we are crossing two heterozygote pea plants (Tt x Tt). The Punnett square for this cross would look like this: T t T TT Tt t Tt tt From the Punnett square, we can see that there are four possible genotypes for the offspring: TT (homozygous dominant), Tt (heterozygous), tT (also heterozygous), and tt (homozygous recessive). The probability of producing a heterozygote offspring (Tt or tT) is 2 out of the 4 possible outcomes, which simplifies to: 2/4=