Ice of mass 50g at 0°C was completely melted by 70% of the total heat...
PHYSICS
WAEC 2017
Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied [Specific latent heat of fusion of ice = 336\(Jg^{-1}\)]
- A. 2400J
- B. 6800J
- C. 7251J
- D. 24000J
Correct Answer: D. 24000J
Explanation
The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)
Q = \(50 \times 336 = 16800J\) but this is 70% of the total heat supplied so that we have,
70% total heat = 16800J
\(\frac{70}{100}\) of total heat = 16800J
⇒ Total heat supplied = \(\frac{16800\times100}{70} = 24000J\)
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