The p.d across a parallel-plate capacitor is 10 3 V. If the distance between the
PHYSICS
WAEC 2016
The p.d across a parallel-plate capacitor is 103V. If the distance between the two plates is 10cm. Calculate the magnitude of the electric field strength between the plates.
- A. 1.0 x 104Vm-1
- B. 1.0 x 105Vm-1
- C. 1.5 x 105Vm-1
- D. 2.0 x 105Vm-1
Correct Answer: A. 1.0 x 104Vm-1
Explanation
E = \(\frac{v}{d} = \frac{10^3}{0.1}\)
= 10000
= 1.0 x 104Vm-1
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