A man and his friend have masses 70kg and 60kg respectively. If they are seated...
PHYSICS
WAEC 2016
A man and his friend have masses 70kg and 60kg respectively. If they are seated 1.0m apart, calculate the gravitational force of attraction between them. (G = 6.67 x 10-11 Nm2 kg-2)
- A. 1.59 x 10-14 N
- B. 2.80 x 10-7 N
- C. 1.30 x 10-2 N
- D. 6.30 x 1013 N
Correct Answer: B. 2.80 x 10-7 N
Explanation
F = \(\frac{GM_1M_}{r^2}\)
= \(\6.67 \times 10^{-11} \times 70 \times 60}{1^2}\)
= 2.8014 x 10-7 N
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *

