A man and his friend have masses 70kg and 60kg respectively. If they are seated...

PHYSICS
WAEC 2016

A man and his friend have masses 70kg and 60kg respectively. If they are seated 1.0m apart, calculate the gravitational force of attraction between them. (G = 6.67 x 10-11 Nm2 kg-2)

  • A. 1.59 x 10-14 N
  • B. 2.80 x 10-7 N
  • C. 1.30 x 10-2 N
  • D. 6.30 x 1013 N

Correct Answer: B. 2.80 x 10-7 N

Explanation

F = \(\frac{GM_1M_}{r^2}\)

= \(\6.67 \times 10^{-11} \times 70 \times 60}{1^2}\)

= 2.8014 x 10-7 N



Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *
Add Math
Don't want to keep filling in name and email whenever you make a contribution? Register or login to make contributing easier.