A stone projected horizontally from the top of a tower with a speed of 4
PHYSICS
WAEC 2011
A stone projected horizontally from the top of a tower with a speed of 4 ms\(^{-1}\) lands on the level ground at a horizontal distance of 25 m from the foot of the tower. Calculate the height of the tower. = 10 ms\(^{-2}\)]
Explanation
R = U\(\sqrt{\frac{2h}{g}}\)
h = \(\frac{R^2g}{2u^2}\)
= \(\frac{25^2 \times 10}{2 \times 4^2}\)
= 195.3m
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *