(a) State three conclusions that can be drawn from Rutherford's experiment on the scattering of...

PHYSICS
WAEC 2010

(a) State three conclusions that can be drawn from Rutherford's experiment on the scattering of alpha particles by a thin metal foil in relation to the structure of the atom

a

The diagram below illustrates th3 energy levels of an electron in an atom. If an excited electron moves from n\(_2\) to n\(_\theta\), calculate the:

(i) frequency;

(ii) wavelength of the emitted radiation. [ h = 6.6 x 10\(^{-34}\) Js; le V = .6 x 10\(^{-19}\) J; C = 3.0 x 10\(^8\) ms\(^{-1}\)]

(c) The following nuclear equations represent two types of radioactivity.

\(^{226}_{88}R_a \to ^{222}_{86}R_n + ^a_2a\) (Equation A)

\(^{14}_7N + ^4_2a \to ^{17}_8O + ^1_1p\) (Equation B)

Identify each type and explain briefly the difference between them

Explanation

(a) Conclusion from Rutherford's experiment;

- The nucleus is massive

- Most of the atom is empty space

- The nucleus is positively charged

- Electrons revolve round the nucleus

- It explains the periodicity of elements in the periodic table

b )(i) E\(_2\) = E\(_2\) - E\(_o\)

= - 2.0 - (-12.0)

= 10.0 e V

= 10 x 1.6 x 1O\(^{-19}\)J

= 1.6 x 10\(^{-18}\)J

E = hf

Or

f = E/h

= 1.6 x 10\(^{18}\)

= 6.6 x10\(^{-34}\)

= 2.424 x 10\(^{15}\) Hz

(ii) c = fλ

λ= c/f

= 3 x 10\(^8\)

2.424 x 10\(^{15}\) Hz

(c) A: Natural radioactivity

B: Artificial radioactivity

Any correct difference

b



Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *
Add Math
Don't want to keep filling in name and email whenever you make a contribution? Register or login to make contributing easier.