A particle is projected horizontally at 15ms\(^{-1}\) from a height of 20m. Calculate the horizontal...
PHYSICS
WAEC 2009
A particle is projected horizontally at 15ms\(^{-1}\) from a height of 20m.
Calculate the horizontal distance covered by the particle just before hitting the ground.
[g = 10 ms\(^{-2}\)]
Explanation
The expected answer is:
Let R represent the horizontal distance covered at time, t.
h = ½ gt\(^2\)
20 = ½ x 10 x t\(^2\)
t = 2 s
R = ut
= 15 x 2
= 30m
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