A Spiral spring of natural length 20.00cm has a scale hanging freely in its lower...

PHYSICS
WAEC 2004

A Spiral spring of natural length 20.00cm has a scale hanging freely in its lower end. When an object ass 40 g is placed in the pan. its length becomes cm. When the object is replaced with another of 60g, the length becomes 22.05cm. Calculate the mass scale pan. [g = 10 ms\(^{-2}\)]

Explanation

Mg = Ke ; (m + 40)g = 1.80k .................. (i)

(m + 60)g = 2.05K ................ (ii)

\(\frac{m + 40}{m + 60} = \frac{1.80}{2.05}\)

1.80 (m + 60) = 2.05 (m + 40)

m = \(\frac{26}{0.25} = 104g\)



Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *
Add Math
Don't want to keep filling in name and email whenever you make a contribution? Register or login to make contributing easier.