Find the equation of a straight line passing through the point (1, -5) and having
MATHEMATICS
WAEC 2019
Find the equation of a straight line passing through the point (1, -5) and having gradient of \(\frac{3}{4}\)
- A. 3x + 4y - 23 = 0
- B. 3x + 4y +23 = 0
- C. 3x - 4y +23 = 0
- D. 3x - 4y - 23 = 0
Correct Answer: D. 3x - 4y - 23 = 0
Explanation
\(\frac{3}{4} = \frac{y + 5}{x - 1}\)
3(x - 1) = 4(y + 5)
3x - 3 = 4y + 20
3x - 4y - 23 = 0
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *