200g of water at 90°C is mixed with 100g of water at 30°C. What is...
PHYSICS
JAMB 1993
200g of water at 90°C is mixed with 100g of water at 30°C. What is the final temperature?
- A. 50oC
- B. 60oC
- C. 70oC
- D. 80oC
Correct Answer: C. 70oC
Explanation
Heat lost = heat gained
200 x c x (90 - \(\theta\))= 100\(\times\) c \(\times\) (\(\theta - 30\))
Dividing through by 100c, we have
2(\(90 - \theta\)) = (\(\theta - 30\))
simplifying, we have
\(\theta\) = 70°
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