The external and internal diameter of a tube are measured as (32 ± 2)mm and
PHYSICS
JAMB 1993
The external and internal diameter of a tube are measured as (32 ± 2)mm and (21 ± 1)mm respectively. Determine the percentage error in the thickness of the tube.
- A. 27%
- B. 14%
- C. 9%
- D. 3%
Correct Answer: C. 9%
Explanation
Actual thickness = 34 - 22 = 12
error thickness = 30 - 20 = 10
error = 12 - 10 = 2mm that is, (11 ± 1)mm
%error = \(\frac{1}{11}\) x \(\frac{100}{1}\)
= 9%
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