Correct Answer: A)

C\(_3\)H\(_6\)

Explanation

To find the formula of the hydrocarbon, we need to determine its molar mass and the moles of the hydrocarbon. Since we know the mass and volume of the hydrocarbon at Standard Temperature and Pressure (S.T.P.), we can use the molar volume of a gas at S.T.P., which is 22.4 dm\(^3\), or 22,400 cm\(^3\).

First, let's find the moles of the hydrocarbon:

\[\text{moles} = \frac{\text{volume at S.T.P.}}{\text{molar volume at S.T.P.}}\]

\[\text{moles} = \frac{32 \text{ cm}^3}{22,400 \text{ cm}^3}\]

\[\text{moles} = 1.43 \times 10^{-3}\]

Now, let's find the molar mass of the hydrocarbon:

\[\text{molar mass} = \frac{\text{mass}}{\text{moles}}\]

\[\text{molar mass} = \frac{0.06 \text{ g}}{1.43 \times 10^{-3}}\]

\[\text{molar mass} \approx 42 \text{ g/mol}\]

We can now determine the empirical formula of the hydrocarbon. We know that it consists of carbon (C) and hydrogen (H) atoms. The atomic mass of carbon is 12 g/mol and the atomic mass of hydrogen is 1 g/mol. Let's use x as the number of carbon atoms and y as the number of hydrogen atoms in the formula:

\[12x + y = 42\]

We'll now consider the possible options and see which fits the equation:

Option A: C\(_3\)H\(_6\) (Correct)

In this formula, x = 3, and y = 6. The equation becomes 12(3) + 6 = 42, which is true. So, Option A is correct.

Option B: C\(_2\)H\(_2\)

In this formula, x = 2, and y = 2. The equation becomes 12(2) + 2 = 26, which is not equal to 42. So, Option B is incorrect.

Option C: C\(_2\)H\(_4\)

In this formula, x = 2, and y = 4. The equation becomes 12(2) + 4 = 28, which is not equal to 42. So, Option C is incorrect.

Option D: C\(_2\)H\(_6\)

In this formula, x = 2, and y = 6. The equation becomes 12(2) + 6 = 30, which is not equal to 42. So, Option D is incorrect.

Therefore, the correct formula for the hydrocarbon is C\(_3\)H\(_6\).

Explanation

(a) Chlorine is used as a bleaching and in the manufacture of bleaching agents. Chlorine is also used as domestic antiseptic solution such as sodium oxochlorate

(i) NaOCI.

(ii) Chlorine is an acidic gas and therefore, in its contact with moist blue litmus paper will first turn the paper red before bleaching it.

(b) Laboratory preparation of a dry sample of chlorine \(MnO_2{(s)} + 4HCl_{(aq)} \to MnCl_{2(aq)} + 2H_2O_{(l)} + Cl_{2(g)}\)

(c)(i) \(2FeCl_{2(g)} + Cl_{2(g)} \to 2FeCl_{3(aq)}\) (Redox reaction)

(green) (red brown)

(ii) \(H_2C=Ch-CH_{3(g)} + Cl_{_(g)}\) \(\to\) \(CH_2ClCHClCH_3\) (addition type reaction)

(ii) The product in (c)(ii) is called 1, 2-dichloropropane.

(d)

Cl\(_{2(g)}\) oxides 2Br\(^-\) to Br\(_{2(l)}\) while F\(_{2(g)}\) oxides 2Cl\(^{-}\) to Cl\(_{2(g)}\)

Correct Answer: B) orange to green

Correct Answer: B) 1.26mole

Correct Answer: C) (c)

Correct Answer: C. 0.25 mol dm^-3

Correct Answer: D. CaO

Correct Answer: D) benzene

Correct Answer: A) ionic, covalent and dative

Explanation

Ammonium chloride is a compound made up of two ions: ammonium (NH4+) and chloride (Cl-). The bonding between these ions can be classified as ionic, covalent, and dative.

Ionic bonding occurs when there is a transfer of electrons from one atom to another, resulting in the formation of oppositely charged ions. In ammonium chloride, the ammonium ion donates a hydrogen ion to the chloride ion, forming NH4+ and Cl-. This results in ionic bonding between the two ions.

Covalent bonding occurs when two or more atoms share electrons to form a bond. In ammonium chloride, there is a covalent bond between the nitrogen atom in the ammonium ion and the four hydrogen atoms that surround it.

Lastly, dative bonding (also known as coordinate covalent bonding) occurs when one atom donates a pair of electrons to another atom to form a covalent bond. In ammonium chloride, the nitrogen atom in the ammonium ion donates a pair of electrons to the chlorine atom, forming a dative bond.

Therefore, the correct answer to this question is Option A: ionic, covalent, and dative.

Correct Answer: B. fungicide