Correct Answer: C) oxidized to oxygen

Explanation

In the given reaction, ozone (O\(_{3(g)}\) reacts with hydrogen peroxide (H\(_2\)O\(_{2(l)}\) to produce water (H\(_2\)O\(_{(l)}\) and oxygen gas (O\(_{2(g)}\).

Ozone is a powerful oxidizing agent, which means it can easily lose electrons and cause other substances to gain those electrons. In this reaction, ozone is being converted to oxygen gas, so it is losing electrons and undergoing oxidation. Therefore, option C (oxidized to oxygen) is the correct answer.

Option A, B, and D are incorrect because:

• Displacement is a type of reaction where an element is replaced by another element in a compound, which is not happening in this reaction.
• Decomposition is a type of reaction where a compound breaks down into simpler substances, and although oxygen gas is formed in this reaction, ozone is not simply breaking down; it is undergoing a redox reaction with hydrogen peroxide.
• Reduction is a type of reaction where a substance gains electrons, and in this reaction, ozone is losing electrons, not gaining them.

Correct Answer: A) HNO3

Correct Answer: B. heating at a high temperature

Correct Answer: B) good oxidizing agents

Correct Answer: C. 2.24 dm³

Explanation

(a) Paper chromatography

(b)(i) Three

(ii) Carbontetrachloride (CCI\(_4\))

(iii) Ill marks the point of application of the indicator.

Correct Answer: A. thermosetting

Correct Answer: A) 58.07

Explanation

To determine the relative molecular mass of the gas, we need to use the ideal gas equation:

\(PV = nRT\)

where \(P\) is the pressure, \(V\) is the volume, \(n\) is the amount of substance in moles, \(R\) is the gas constant, and \(T\) is the temperature in Kelvin.

First, convert the temperature to Kelvin:

\(T = 20^{\circ}C + 273.15 = 293.15K\)

Next, convert the volume to meters cubed:

\(V = 512 cm^3 = 0.000512 m^3\)

Now, we can rearrange the ideal gas equation to solve for the amount of substance, \(n\):

\(n = \frac{PV}{RT}\)

Substitute the given values:

\(n = \frac{(1 atm)(0.000512 m^3)}{(8.314 JK^{-1}mol^{-1})(293.15K)}\)

Convert the pressure from atm to J m\(^{-3}\):

\(1 atm = 101,325 J m^{-3}\)

\(n = \frac{(101,325 J m^{-3})(0.000512 m^3)}{(8.314 JK^{-1}mol^{-1})(293.15K)}\)

Calculate \(n\):

\(n \approx 0.0213 mol\)

Now, we can determine the relative molecular mass by dividing the mass of the gas by the amount of substance:

Relative Molecular Mass = \(\frac{mass}{moles}\)

Relative Molecular Mass = \(\frac{1.236g}{0.0213 mol} \approx 58.07\)

So, the correct answer isOption A: 58.07.

Explanation

(a) Uses of Na\(_2\)CO\(_3\)

- As a water softener

- For standardizing acids or as analytical reagent

- In the manufacture of glass. NaOH, paper, soap or detergent etc.

(b)(i) Hydrolysis accounts for the alkalinity of Na\(_2\)CO\(_3\)\(_{(aq)}\)

(ii) Sodium hydrogen trioxocarbonate (IV) is obtained when

- CO\(_2\) is bubbled into Na\(_2\)CO\(_{3(aq)}\).

Correct Answer: B) NH₃