Correct Answer: D) warned his sons but did not punish them

Explanation

The question is asking about God's revelation to Samuel concerning the punishment of Eli. According to the Bible, Eli was a priest and judge in Israel who had two sons that were committing sinful acts. God revealed to Samuel that He was going to punish Eli for a specific reason. The question provides four options to choose from, and we are to select the correct one.

Option A states that Eli did not correct his sons' sinful behavior. While this is true, it is not the reason why God revealed to Samuel that He was going to punish Eli.

Option B states that Eli did not offer sacrifice as the law required. This is also true, but it is not the reason why God revealed to Samuel that He was going to punish Eli.

Option C states that Eli did not warn the people of Israel to stop sinning. This is also true, but it is not the reason why God revealed to Samuel that He was going to punish Eli.

Option D states that Eli warned his sons but did not punish them. This is the correct option. God revealed to Samuel that He was going to punish Eli because he did not punish his sons for their sinful behavior, even though he warned them about the consequences of their actions.

In summary, Option D is the correct answer to the question. It is important to understand that Eli's failure to punish his sons for their sinful behavior was the reason why God revealed to Samuel that He was going to punish Eli.

Correct Answer: D. clay

Correct Answer: B. wage

Correct Answer: D. labour

Explanation

(a) (i) - action of an acid upon an active metal / metals higher than hydrogen in the reactivity series

- preparation by double decomposition (reaction between two soluble compounds to produce an insoluble compound)

- by neutralization (reaction between acids & bases)

- action of an acid on trioxocarbonate (IV) of a metal

- direct combination of elements

- action of dilute acid on an insoluble base

Examples:

(ii) - Addition of granulated zinc to a dilute solution of tetraoxosulphate (VI) acid.

Zn(s) + H\(_2\)SO\(_{4(aq)}\) → ZnSO\(_{4(aq)}\) + H\(_{2(g)}\)

- Pb(NO\(_3\))\(_{2(aq)}\) + H\(_2\)SO\(_{4(aq)}\) → PbSO\(_{4(s)}\) + 2HNO\(_{3(aq)}\)

OR

Pb(NO\(_3\))\(_{2(aq)}\) + Na\(_{2}\)SO\(_{4(aq)}\) → PbSO\(_{4(s)}\) + 2NaNO\(_{3(aq)}\)

2NaOH\(_{(aq)}\) + H\(_{2}\)SO\(_{4(aq)}\) → Na\(_2\)SO\(_{4(aq)}\) + 2H\(_2\)O\(_{(l)}\)

ZnCO\(_{3(s)}\) + H\(_2\)SO\(_{4(aq)}\) → ZnSO\(_{4(aq)}\) + H\(_2\)O\(_{(l)}\) + CO\(_{2(g)}\)

- CaCO\(_{3(s)}\) + 2HCl\(_{(aq)}\) → CaCl\(_{2(aq)}\) + H2O\(_{(l)}\) + CO\(_{2(g)}\)

- 2Fe + 3Cl\(_2\) → 2FeCl\(_3\)

Fe + S → FeS

- 2HNO\(_3\) + CuO → Cu(NO\(_3\))\(_2\) + H\(_2\)O

(iii) Uses of Na\(_2\)CO\(_3\)

- used as a water softner

- manufacture of glass/paper/rayon/soaps/detergents/NaOH/Borax

- food processing aid

- pH modifier

- swimming pool chemical

- electrolyte

- analytical reagent / standardization of acids

(b) Use pure copper as the cathode and impure copper as anode and then use a named soluble copper salt e.g. CuSO\(_4\) solution as the electrolyte impure copper dissolves /CuCu\(^{2+}\) + 2e\(^-\) and will be deposited at cathode / Cu\(^{2+}\) + 2e\(^-\) Cu Wash the cathode to obtain pure copper.

(c) (i) Mass of NaCl deposited = 39.0 – 36.3 g = 2.7 g

% NaCl deposited = 2.7 x \(\frac{100}{39.0}\) = 6.92 % or 7.0%

Mass of AgNO\(_3\) deposited = 952.0 – 297.0 = 655 g

% AgNO\(_3\) = \(\frac{655}{952}\) x 100 = 68.8 % Or 69%

(ii) AgNO\(_3\) (Silver trioxonitrate (V)) will be more efficiently crystallized because it has a higher percentage deposited.

Correct Answer: A. trusted

Explanation

staunch; very loyal and committed in attitude. Trust worthy.

Correct Answer: A. Moral Philosophy

Correct Answer: D. Promoting racial discrimination

Correct Answer: C. \(\frac{1}{2(x - 2)} + \frac{5x}{2(x- 2)^{2}}\)

Explanation

\(\frac{3x - 1}{(x - 2)^{2}} = \frac{A}{(x - 2)} + \frac{Bx}{(x - 2)^{2}}\)

\(\frac{3x - 1}{(x - 2)^{2}} = \frac{A(x - 2) + Bx}{(x - 2)^{2}}\)

Comparing, we have

\(3x - 1 = Ax - 2A + Bx \implies -2A = -1; A + B = 3\)

\(\therefore A = \frac{1}{2}; B = \frac{5}{2}\)

= \(\frac{1}{2(x - 2)} + \frac{5x}{2(x - 2)^{2}}\)

Correct Answer: C. 960Ω

Explanation

R = \(\frac{V^2}{P} = \frac{240^2}{60} = 960\Omega\)