Correct Answer: B. 28

Correct Answer: C. Fosuwa

Correct Answer: C. upper fixed point of a thermometer

Correct Answer: B. humour, rhyme scheme and five lines

Correct Answer: d) Peninsula

Correct Answer: D) Amino acids

Explanation

Proteins are complex molecules that are essential for various functions in the body. They can be found in many foods such as meat, fish, eggs, and beans. When proteins are broken down, they provide different substances that the body needs. The question is asking what substance is provided when proteins are broken down. The options provided are Oxygen, Carbohydrate, Energy, and Amino acids. Out of these options, the correct answer is Amino acids. Amino acids are the building blocks of proteins, and when proteins are broken down, they are broken down into individual amino acids. These amino acids can then be used by the body to build new proteins, or they can be broken down further to provide energy or other substances that the body needs. It is important to note that while proteins can provide energy when they are broken down, the primary source of energy in the body is carbohydrates and fats. Additionally, oxygen is not directly provided when proteins are broken down, although it is needed for the process of breaking down proteins to occur. In summary, when proteins are broken down, they provide amino acids, which are the building blocks of proteins and can be used to build new proteins or provide the body with energy and other substances it needs.

Correct Answer: D. Magnified

Explanation

The image formed by a plane mirror is always virtual (the light rays do not actually come from the image), upright, and of the same shape and size as the object it is reflecting.

Correct Answer: B. develop and implement policies effectively

Correct Answer: A. 1835/1840

Explanation

(a) \(\sqrt{4x - 3} - \sqrt{2x - 5} = 2\)

Squaring both sides, we have

\(4x - 3 - 2\sqrt{8x^{2} - 26x + 15} + 2x - 5 = 4\)

\(6x - 8 - 4 = 2\sqrt{8x^{2} - 26x + 15}\)

\(6x - 12 = 2\sqrt{8x^{2} - 26x + 15}\)

\(3x - 6 = \sqrt{8x^{2} - 26x + 15}\)

Squaring both sides, we have

\(9x^{2} - 36x + 36 = 8x^{2} - 26x + 15\)

\(9x^{2} - 8x^{2} - 36x + 26x + 36 - 15 = 0\)

\(x^{2} - 10x + 21 = 0\)

Factorising, we have

\((x - 7)(x - 3) = 0\)

\(\text{x = 7 or 3}\).

(b)

We integrate with respect to y.

\(y^{2} = 4x \implies x = \frac{y^{2}}{4}\)

\(x + y = 0 \implies x = -y\)

To get the boundary, equate the two values of x;

\(\frac{y^{2}}{4} = - y \implies y^{2} = -4y\)

\(y^{2} + 4y = 0 \implies y(y + 4) = 0\)

\(y = 0; y = -4\)

\(\int_{-4}^{0} (\frac{y^{2}}{4}) \mathrm {d} y = [\frac{y^{3}}{12}]|_{-4}^{0}\)

\(0 - \frac{-4^{3}}{12} = 0 - \frac{-64}{12} = \frac{64}{12} sq. units\)

\(\int_{-4}^{0} - y \mathrm {d} y = [-\frac{y^{2}}{2}]|_{-4}^{0}\)

\(0 - \frac{-(-4^{2})}{2} = \frac{16}{2} = 8 sq. units\)

Area enclosed = \(8 - \frac{64}{12} = \frac{32}{12} = 2\frac{2}{3} sq. units\)