Correct Answer: A. Advertising is paid for while publicity is not

Correct Answer: A. to helping

Explanation

The correct answer is A. to helping.

Explanation:

The phrase devote oneself is followed by the preposition to. When to is a preposition, it must be followed by a noun or a gerund (the -ing form of a verb acting as a noun).

• Helping is a gerund, functioning as a noun that describes the activity he devoted himself to.

Let's look at why the other options are incorrect:

• B. to help: This is an infinitive. While to can introduce an infinitive, in the phrase devote oneself to..., to acts as a preposition, not as part of an infinitive marker.

• C. by helping: By helping implies the *method* or *means* by which he devoted himself, which doesn't fit the idiom devote oneself to [something].

• D. with helping: With helping is not the correct idiomatic preposition to follow devote oneself.

Therefore, the complete sentence is: He devoted himself to helping homeless children.

Correct Answer: B. Carolus Linnaeus

Correct Answer: D. non-bank financial institutions

Correct Answer: A. pottery

Correct Answer: A)

C\(_3\)H\(_6\)

Explanation

To find the formula of the hydrocarbon, we need to determine its molar mass and the moles of the hydrocarbon. Since we know the mass and volume of the hydrocarbon at Standard Temperature and Pressure (S.T.P.), we can use the molar volume of a gas at S.T.P., which is 22.4 dm\(^3\), or 22,400 cm\(^3\).

First, let's find the moles of the hydrocarbon:

\[\text{moles} = \frac{\text{volume at S.T.P.}}{\text{molar volume at S.T.P.}}\]

\[\text{moles} = \frac{32 \text{ cm}^3}{22,400 \text{ cm}^3}\]

\[\text{moles} = 1.43 \times 10^{-3}\]

Now, let's find the molar mass of the hydrocarbon:

\[\text{molar mass} = \frac{\text{mass}}{\text{moles}}\]

\[\text{molar mass} = \frac{0.06 \text{ g}}{1.43 \times 10^{-3}}\]

\[\text{molar mass} \approx 42 \text{ g/mol}\]

We can now determine the empirical formula of the hydrocarbon. We know that it consists of carbon (C) and hydrogen (H) atoms. The atomic mass of carbon is 12 g/mol and the atomic mass of hydrogen is 1 g/mol. Let's use x as the number of carbon atoms and y as the number of hydrogen atoms in the formula:

\[12x + y = 42\]

We'll now consider the possible options and see which fits the equation:

Option A: C\(_3\)H\(_6\) (Correct)

In this formula, x = 3, and y = 6. The equation becomes 12(3) + 6 = 42, which is true. So, Option A is correct.

Option B: C\(_2\)H\(_2\)

In this formula, x = 2, and y = 2. The equation becomes 12(2) + 2 = 26, which is not equal to 42. So, Option B is incorrect.

Option C: C\(_2\)H\(_4\)

In this formula, x = 2, and y = 4. The equation becomes 12(2) + 4 = 28, which is not equal to 42. So, Option C is incorrect.

Option D: C\(_2\)H\(_6\)

In this formula, x = 2, and y = 6. The equation becomes 12(2) + 6 = 30, which is not equal to 42. So, Option D is incorrect.

Therefore, the correct formula for the hydrocarbon is C\(_3\)H\(_6\).

Correct Answer: D. Makkan Suwar are short and poetic while the Madinan Suwar are longer and generic

Correct Answer: D. energy expended per unit time

Explanation

(a) Doping is the introduction of impurity atoms into a semicondoctor

(b) Doping increases the conductivity of a semicondoctor by increasing the number of chargers or electron or holes.

Correct Answer: A. 5' - TAGCTTCACG - 3'

Explanation

The question specifies that this is DNA replication. U (uracil) is found only in RNA and T (thymine) is found only in DNA. In DNA, A (adenine) pairs with T (thymine) and G (guanine) pairs with C (cytosine) so the complementary strand will have A where the original has T, G where the original has C, C where the original has G and T where the original has A. DNA strands run antiparallel, so the 3' end on the new strand will go opposite the 5' end on the original and vice versa. In this case, that means the complementary strand will run from 5' to 3' to read 5' - TAGCTTCACG - 3'. This sequence is shown in bold below: