Correct Answer: B. hamartia

Correct Answer: A. direct materials+direct labour+direct wages

Correct Answer: B. Abolition of slave trade and the need for raw materials.

Correct Answer: C. Kidding

Explanation

Kidding is not branch of agriculture. It is the act of giving birth in rabbits and goats. Choice C is correct

Explanation

(a) Total amount budgeted: $6,250 + $2,150 + $4,300 + $2,400 + $2,900 = $18,000.

Education = \(\frac{6,250}{18,000}\) x 360 = 125°

Mining = \(\frac{2,150}{18,000}\) x 360 = 43°

Agriculture = \(\frac{4,300}{18,000}\) x 360 = 86°

Communication = \(\frac{2,400}{18,000}\) x 360 = 48°

Health = \(\frac{2,900}{18,000}\) x 360 = 58°

A pie chart showing budgetary allocations of a country for selected sectors of the economy.

(b) A budget surplus occurs when a governments planned revenue is more that its planned expenditure.

While a budget deficit occurs when the planned expenditure is more than the planned revenue.

Correct Answer: C. 15 J

Explanation

The problem asks for the total energy of a ball just before it hits the ground. We are given the mass of the ball, its initial speed, the height of the tower, and we need to neglect air resistance. In such a scenario, the total mechanical energy of the ball is conserved.

The total mechanical energy (E) is the sum of its kinetic energy (KE) and potential energy (PE).

E = KE + PE

Let's set the ground as the reference level for potential energy, so PE = 0 at the ground.

Given:

Mass of the ball, m = 0.1 kg

Initial speed, u = 10 ms⁻¹

Height of the tower, h = 10 m

Acceleration due to gravity, g = 10 ms⁻²

1. Calculate the initial total energy of the ball (at the top of the tower):

• Initial Kinetic Energy (KE_initial):

KE_initial = (1/2) * m * u²

KE_initial = (1/2) * 0.1 kg * (10 ms⁻¹)²

KE_initial = (1/2) * 0.1 * 100

KE_initial = 0.5 * 10 = 5 J

• Initial Potential Energy (PE_initial):

The ball is at a height h = 10 m above the ground.

PE_initial = m * g * h

PE_initial = 0.1 kg * 10 ms⁻² * 10 m

PE_initial = 0.1 * 100 = 10 J

• Total Initial Energy (E_initial):

E_initial = KE_initial + PE_initial

E_initial = 5 J + 10 J = 15 J

2. Apply the principle of conservation of mechanical energy:

Since air resistance is neglected, the total mechanical energy of the ball remains constant throughout its flight. This means the total energy just before hitting the ground will be equal to the total initial energy.

E_final (just before hitting the ground) = E_initial

E_final = 15 J

Alternatively, we can calculate the final kinetic energy just before hitting the ground:

Using kinematics:

The ball is thrown upwards with u = 10 m/s.

The displacement from the top of the tower to the ground is s = -10 m (taking upwards as positive).

Acceleration a = -g = -10 m/s².

Using the equation v² = u² + 2as:

v² = (10)² + 2 * (-10) * (-10)

v² = 100 + 200

v² = 300

Final Kinetic Energy (KE_final):

KE_final = (1/2) * m * v²

KE_final = (1/2) * 0.1 kg * 300 (ms⁻¹)²

KE_final = (1/2) * 30 = 15 J

Just before hitting the ground, the height is 0, so Potential Energy (PE_final) = 0.

Total energy just before hitting the ground = KE_final + PE_final = 15 J + 0 J = 15 J.

Both methods yield the same result.

The final answer is 15 J.

Explanation

(a)

(b) From the figure above,

(i) |WZ| = 5.25 cm ; (ii) |ZN| = 4.86 cm.

Correct Answer: D. can sue and be sued

Correct Answer: B. 2[1-3m]

Explanation

\(\frac{2-18m^2}{1+3m}\) = \(\frac{2[1-9m^2]}{1+3m}\)

\(\frac{2[1-3m][1+3m]}{1+3m}\)

2[1-3m]

Correct Answer: C) It is an oxidising agent