In the diagram, O is the center of the circle QRS and ∠SQR = 28°....
MATHEMATICS
WAEC 2023
In the diagram, O is the center of the circle QRS and ∠SQR = 28°. Find ∠ORS.
- A. \(56^0\)
- B. \(28^0\)
- C. \(76^0\)
- D. \(62^0\)
Correct Answer: D. \(62^0\)
Explanation
∠SOR = 2 × 28° = 56° (angle at the centre is twice the angle at the circumference)
From ?SOR
|OS| = |OR| (radii)
So, ?SOR is isosceles.
∠ORS = \(\frac{180^0 - 56^0}{2} = \frac{124^0}{2}\) ( base angles of isosceles triangle are equal)
∴ ∠ORS = 62°
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *