Find the coefficient of the \(6^{th}term\) in the binomial expansion of \((1 - \frac{2x}{3})10\) in...
FURTHER MATHEMATICS
WAEC 2023
Find the coefficient of the \(6^{th}term\) in the binomial expansion of \((1 - \frac{2x}{3})10\) in ascending powers of \(x\).
- A. \(-\frac{896x^6}{9}\)
- B. \(-\frac{896x^5}{9}\)
- C. \(-\frac{896x^5}{27}\)
- D. \(-\frac{896x^6}{27}\)
Correct Answer: C. \(-\frac{896x^5}{27}\)
Explanation
rth term of a binomial expansion =\(^nC_r-1 a^{n-(r-1)}b^{r-1}\)
\(n = 10,r = 6 \therefore r-1=5\)
6th term =\(^{10}C_5 1^{10} - 5 (-\frac{2}{3}x)^5\)
\(=252*1*-\frac{32x^5}{243}=-\frac{896x^5}{27}\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *