The velocity of a body of mass 4.56 kg increases from \((10 ms^{-1}, 060^o) to
FURTHER MATHEMATICS
WAEC 2023
The velocity of a body of mass 4.56 kg increases from \((10 ms^{-1}, 060^o) to (50 ms ^{-1}, 060^o)\) in 16 seconds . Calculate the magnitude of force acting on it.
- A. 17.1 N
- B. 11.4 N
- C. 36.5 N
- D. 5.7 N
Correct Answer: B. 11.4 N
Explanation
\(m=4.56kg;t=16s;v_1=(10ms^{-1},060^o);v_2=(50ms^{-1},060^o)\)
Notice that there is no change in the direction of the velocity
So,we don't need to write it in a vector form
\(a=\frac{?v}{t}=\frac{50 - 10}{16}\)
\(a=\frac{40}{16}=2.5ms^{-2}\)
F = ma = 4.56 x 2.5
∴ F = 11.4 N
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *