200 tickets were sold for a show. VIP tickets costs N1,200 and N700 for regular.

MATHEMATICS
JAMB 2023

200 tickets were sold for a show. VIP tickets costs N1,200 and N700 for regular. Total amount realised from the sale of the tickets was N180,000. Find the number of VIP tickets sold and the the number of regular ticket sold.

  • A. VIP = 80, Regular = 100
  • B. VIP = 60, Regular = 120
  • C. VIP = 60, Regular = 100
  • D. VIP = 80, Regular = 120

Correct Answer: D. VIP = 80, Regular = 120

Explanation

Let \(x\) = number of VIP tickets sold and

\(y\) = number of regular tickets sold

Total number of tickets sold = 200

⇒ \(x\) + \(y\) = 200 ---- (i)

If it costs N1,200 for a VIP ticket, then it costs N1200x for \(x\) number of VIP tickets sold and

If it costs N700 for a regular ticket, then it costs N700\(y\) for \(y\) number of VIP tickets sold

The total amount realised from the sale of tickets = N180,000

⇒ 1200\(x\) + 700\(y\) = 180000 ----- (ii)

From equation (i)

\(x\) = 200 - \(y\) ----- (iii)

Substitute (200 - \(y\)) for \(x\) in equation (ii)

⇒ 1200(200 - \(y\)) + 700\(y\) = 180000

⇒ 240000 - 1200\(y\) + 700\(y\) = 180000

⇒ 240000 - 500\(y\) = 180000

Collect like terms

⇒ 240000 - 180000 = 500\(y\)

⇒ 60000 = 500\(y\)

⇒ \(y = \frac{60000}{500} = 120\)

Substitute 120 for \(y\) in equation (iii)

⇒ \(x = 200 - 120\)

⇒ \(x = 80\)

∴ The total number of VIP tickets sold is 80 and regular is 120



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