A charge of \(4.6 × 10^-5\)C is placed in an electric field of intensity \(3.2
PHYSICS
JAMB 2023
A charge of \(4.6 × 10^-5\)C is placed in an electric field of intensity \(3.2 × 10^4\) \(Vm^-1\). What is the force acting on the electron?
- A. 1.5 N
- B. 3.7 N
- C. 4.2 N
- D. 2.5 N
Correct Answer: A. 1.5 N
Explanation
q=\(4.6 × 10^-5\), C= \(3.2 × 10^4\) \(V^m-1\) F= ?
F=qE
⇒ \(4.6 × 10^-5\)C × \(3.2 × 10^4\)
; F= 1.5 N
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