What is the amount of heat required to raise the temperature of a 0.02 kg
What is the amount of heat required to raise the temperature of a 0.02 kg of ice cube from \(-10^oC\) to \(10^oC\) ?
[specific latent heat of fusion of ice = 3.34 x \(10^5\) \(Jkg^-1\), Specific heat capacity of water = 4200 \(Jkg^-1\) \(k^-1\)
Specific heat capacity of ice = 2100 \(Jkg^-1\) \(k^-1\)
- A. 6680 J
- B. 1680 J
- C. 7520 J
- D. 7940 J
Correct Answer: D. 7940 J
Explanation
Quantity of heat required to raise the temperature of the ice cube from \(-10^oC\) to \(0^oC\)
⇒H=mc?ø = 0.02 × 2100 × 10 -(-10)
⇒ H = 0.02 × 2100 × (0 + 10) = 0.02 × 2100 × 10
⇒ H = 420 J
quantity of heat required to melt ice at \(0^oC\)
⇒ H = mL = 0.02 × 4200 × \(10^5\)
⇒H=6680 j
Quantity of heat required to raise the temperature of the melted ice cube (water) from \(0^oC\) to \(-10^oC\)
⇒H=mc?ø = 0.02 × 4200 × (10-0)
⇒H = 0.02 × 4200 × 10
⇒H = 840j
;420 + 6680 + 840 = 7940 j