Find the tension in the two cords shown in the figure above. Neglect the mass...
PHYSICS
JAMB 2023
Find the tension in the two cords shown in the figure above. Neglect the mass of the cords, and assume that the angle is 38° and the mass m is 220 kg
[Take g = 9.8 ms-2]
- A. \(T_1\) = 2864 N, \(T_2\)= 3612 N
- B. \(T_1\)= 3612 N, \(T_2\) = 2864 N
- C. \(T_1\)= 3502 N, \(T_2\)= 2760 N
- D. \(T_1\) = 2760 N, \(T_2\) = 3502 N
Correct Answer: C. \(T_1\)= 3502 N, \(T_2\)= 2760 N
Explanation
W = mg = 220 x 9.8 = 2156 N
⇒Sin 38º = \(\frac{2156}{T_1}\)
⇒ \(T_1\) = \(\frac{2156}{Sin 38}\)
⇒ \(T_1\) = 3502 N
Cos 38º = \(\frac{T_2}{T_1}\)
⇒ \(T_2\) = 3502 x Cos 38º
⇒ \(T_2\) = 2760 N
; \(T_1\) = 3502 N, \(T_2\) = 2760 N.
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