If 100cm 3 of oxygen pass through porous plug in 50 seconds, the time taken
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If 100cm3 of oxygen pass through porous plug in 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is
- A) 10.0s
- B) 12.5s
- C) 17.7s
- D) 32.0s
Correct Answer: B) 12.5s
Explanation
When gases pass through a porous plug, the rate at which they flow through the plug depends on their molecular weights. This concept is described byGraham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
Graham's law can be expressed mathematically as:
\( \frac{Rate_1}{Rate_2} = \sqrt{\frac{M_2}{M_1}} \)
Where:
- Rate_1 andRate_2 are the rates of effusion of gas 1 and gas 2, respectively.
- M_1 andM_2 are the molar masses of gas 1 and gas 2, respectively.
In this question, we are given that 100 cm
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