How many moles of oxygen molecules would be reduced from the decomposition of 2.5 moles
How many moles of oxygen molecules would be reduced from the decomposition of 2.5 moles of potassium trioxochloratc (V)?
- A) 2.50
- B) 3.50
- C) 3.75
- D) 2.50
Correct Answer: C) 3.75
Explanation
Potassium trioxochlorate (V) is also known as potassium chlorate (V) with the chemical formula KClO3. The decomposition of potassium chlorate (V) involves the production of potassium chloride (KCl) and oxygen gas (O2). The balanced chemical equation for this decomposition is:
\(2KClO_3 \rightarrow 2KCl + 3O_2\)
In this equation, 2 moles of potassium chlorate (V) decompose to produce 3 moles of oxygen gas. To find out how many moles of O2 are produced from the decomposition of 2.5 moles of KClO3, we can set up a proportion:
\(\frac{3 \, \text{moles} \, O_2}{2 \, \text{moles} \, KClO_3} = \frac{x \, \text{moles} \, O_2}{2.5 \, \text{moles} \, KClO_3}\)
Now, we can solve for x:
\(x \, \text{moles} \, O_2 = \frac{3 \, \text{moles} \, O_2 \times 2.5 \, \text{moles} \, KClO_3}{2 \, \text{moles} \, KClO_3}\)
\(x \, \text{moles} \, O_2 = 3.75 \, \text{moles} \, O_2\)