120cm\(^3\) of hydrogen were sparked with 60cm\(^3\) of oxygen at 110°C. What was the volume...
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120cm\(^3\) of hydrogen were sparked with 60cm\(^3\) of oxygen at 110°C. What was the volume of swam produced? The equation for the reaction is 2H\(_2\)(g) + O\(_2\)(g) \(\rightarrow\) 2H\(_2\)(g)
- A) 30cm
- B) 60cm
- C) 90cm
- D) 120cm
Correct Answer: A) 30cm
Explanation
2H\(_2\)(g) + O\(_2\)(g) \(\rightarrow\) 2H\(_2\)(g)
By comparing the number of moles, if 120cm\(^3\) of H\(_{2(g)}\) was sparked. 120cm\(^3\) of steam will be produced.
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