Give the total mass of copper in 1gm of copper (II) sulphate [Cu = 40;

Explanation

To answer this question, we need to find the mass percentage of copper in copper (II) sulphate and then use that percentage to calculate the mass of copper in 1 gram of copper (II) sulphate.

First, let's determine the molecular formula of copper (II) sulphate. It is given by the formula CuSO₄, which consists of one copper (Cu), one sulphur (S), and four oxygen (O) atoms.

Next, let's calculate the molar mass of copper (II) sulphate. Using the provided atomic masses, we have:

\(Molar\,mass\,of\,CuSO_4 = Cu + S + 4O = 40 + 32 + 4(16) = 40 + 32 + 64 = 136\,g/mol\)

Now, we can calculate the mass percentage of copper in copper (II) sulphate:

\(Mass\,percentage\,of\,Cu = \frac{Mass\,of\,Cu}{Molar\,mass\,of\,CuSO_4} \times 100 = \frac{40}{136} \times 100 = 29.41\%\)

Finally, let's find the mass of copper in 1 gram of copper (II) sulphate:

\(Mass\,of\,Cu = Mass\,percentage\,of\,Cu \times Mass\,of\,CuSO_4 = 0.2941 \times 1 = 0.2941\,g\)

Since the closest option to our calculated value is 0.25g (Option A), that is the correct answer.