If the rate law obtained for a given reaction is given as rate = K[X]\(^n\)...

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If the rate law obtained for a given reaction is given as rate = K[X]\(^n\) [Y]\(^m\), what is the overall order of the reaction.

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    Options

    \(nm\)
  • B)
    \(\frac{n}{m}\)
  • C)
    \(n+m\)
  • D)
    \(n-m\)

Correct Answer: C)
\(n+m\)

Explanation

The rate law for a given reaction is an equation that relates the rate of the reaction to the concentration of the reactants. In the rate law provided, rate = K[X]\(^n\) [Y]\(^m\), K is the rate constant, [X] and [Y] are the concentrations of the reactants, and n and m are the orders of reaction with respect to X and Y, respectively.

The overall order of a reaction is the sum of the orders of all the reactants involved in the reaction. In this case, the overall order of the reaction is the sum of the orders with respect to X and Y.

So, the overall order of the reaction is:

\[ Overall Order = n + m \]

Therefore, the correct answer isOption C: \(n+m\).



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