The ration of reactants to products is 1: 3: 2 in the reaction represented by
The ration of reactants to products is 1: 3: 2 in the reaction represented by the equation below: N\(_{2(g)}\) +
3H\(_{2(g)}\) \(\rightarrow\) 2NH\(_{3(g)}\). Which of the following laws is demonstrated by this?
- A) Boyle
- B) Law of multiple proportion
- C) Gay Lussac
- D) Law of constant composition
Correct Answer: C) Gay Lussac
Explanation
The given reaction is:
\(N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}\)
The ratio of reactants to products is 1: 3: 2, which means that one mole of nitrogen gas reacts with three moles of hydrogen gas to produce two moles of ammonia gas.
The law that is demonstrated by this reaction isGay Lussac's Law of Combining Volumes. This law states that when gases react together, they do so in volumes that bear a simple whole number ratio to one another, provided that the volumes are measured at the same temperature and pressure.
In this reaction, the volume of nitrogen gas, hydrogen gas, and ammonia gas are in the ratio of 1: 3: 2, which is a simple whole number ratio. Therefore, Gay Lussac's Law is demonstrated by this reaction.