In what way is equilibrium constant for the forward reaction related to that of the...

Explanation

In a reversible chemical reaction, the equilibrium constant for the forward reaction is related to that of the reverse reaction. The correct answer isOption C: The two equilibrium constants are identical.

To understand this concept, let's consider a general reversible reaction:

\(A + B \rightleftharpoons C + D\)

For the forward reaction, the equilibrium constant, \(K_f\), is given by:

\(K_f = \frac{[C][D]}{[A][B]}\)

For the reverse reaction, the equilibrium constant, \(K_r\), is given by:

\(K_r = \frac{[A][B]}{[C][D]}\)

Now, let's look at the relationship between the equilibrium constants of the forward and reverse reactions. The equilibrium constant for the overall reaction, \(K\), is given by:

\(K = \frac{K_f}{K_r}\)

Since the forward and reverse reactions are equal at equilibrium, the overall reaction's equilibrium constant, \(K\), is equal to 1. Therefore, we can write:

\(1 = \frac{K_f}{K_r}\)

From the above equation, we can see that the equilibrium constants for the forward and reverse reactions are reciprocals of each other, which means they are equal when the concentrations of reactants and products are equal at equilibrium. Hence, the two equilibrium constants are identical.