Elements P, Q, R, S, have 6, 11, 15 and 17 electrons respectively, therefore

Explanation

This question is about the electron configuration of four different elements, namely P, Q, R, and S. The question provides the number of electrons for each element, which are 6, 11, 15, and 17 respectively.

Based on this information, the question is asking which of the options best describes the type of bond that would be formed between two of the elements.

Option A suggests that P will form an electrovalent bond with R. An electrovalent bond is also known as an ionic bond, which involves the transfer of electrons from one atom to another. However, the electron configuration of P and R does not suggest that this type of bond would be formed.

Option B suggests that Q will form a covalent bond with S. A covalent bond involves the sharing of electrons between two atoms. This option is a possibility given the electron configuration of Q and S, but it is not the correct answer.

Option C suggests that R will form an electrovalent bond with S. Again, this is an ionic bond, which involves the transfer of electrons from one atom to another. This option is a possibility given the electron configuration of R and S, but it is not the correct answer.

Option D suggests that Q will form an electrovalent bond with S. This is the correct answer because the electron configuration of Q and S suggests that an ionic bond would be formed between the two elements. Q has 11 electrons, which means it has one electron short of a stable configuration, while S has 17 electrons, which means it has one electron more than a stable configuration. Q can transfer an electron to S to form a stable ionic compound.

In summary, the correct answer to this Chemistry question is Option D, which suggests that Q will form an electrovalent bond with S.