The volume of hydrogen gas produced at S.T.P. when 100ml of 2M hydrochloric acid reacts...
CHEMISTRY
POST UTME OAU
The volume of hydrogen gas produced at S.T.P. when 100ml of 2M hydrochloric acid reacts with excess zinc is:
- A)2.24dm\(^3\)
- B)4.48dm\(^3\)
- C)1.12dm\(^3\)
- D)44.8dm\(^3\)
Correct Answer: A)2.24dm\(^3\)
Explanation
First, let's understand the reaction between hydrochloric acid (HCl) and zinc (Zn). The balanced chemical equation for this reaction is:
\(Zn + 2HCl \rightarrow ZnCl_2 + H_2\)
From the balanced equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.
Now, we have 100 mL of 2 M hydrochloric acid, and we need to find the number of moles of HCl in this solution. To do this, we can use the formula:
Moles of solute = Molarity
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