i. NaHCO 3 ii. NaHSO 4 iii. NaCl Which of these will dissolve in water

Explanation

To determine which of these compounds will dissolve in water to give an alkaline solution, we need to understand the properties of each compound and how they behave when they dissolve in water.

i. \(NaHCO_3\)

Sodium bicarbonate, also known as baking soda, is a weak base. When it dissolves in water, it forms a basic solution. The reaction can be represented as follows:

\(NaHCO_3 + H_2O \rightarrow Na^+ + OH^- + H_2CO_3\)

The presence of hydroxide ions (\(OH^-\) in the solution indicates that it is alkaline in nature.

ii. \(NaHSO_4\)

Sodium hydrogen sulfate, also known as sodium bisulfate, is an acidic salt. When it dissolves in water, it forms an acidic solution. The reaction can be represented as follows:

\(NaHSO_4 + H_2O \rightarrow Na^+ + H_3O^+ + HSO_4^-\)

The presence of hydronium ions (\(H_3O^+\) in the solution indicates that it is acidic in nature.

iii. \(NaCl\)

Sodium chloride, also known as table salt, is a neutral salt. When it dissolves in water, it forms a neutral solution. The reaction can be represented as follows:

\(NaCl \rightarrow Na^+ + Cl^-\)

There are no hydroxide ions (\(OH^-\) or hydronium ions (\(H_3O^+\) formed in this reaction, indicating that the solution is neither acidic nor alkaline.

Therefore, the correct answer isOption C: i only, as only sodium bicarbonate (\(NaHCO_3\) dissolves in water to give an alkaline solution.