Given the half-redox reaction O\(_2\) + 4H\(^+\) + 4e\(^-\) \(\rightarrow\) \(2H_2O\), how many moles of...
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Given the half-redox reaction O\(_2\) + 4H\(^+\) + 4e\(^-\) \(\rightarrow\) \(2H_2O\), how many moles of electron will be required produce 3.0 × 1022 molecules of water?
- A) 0.05
- B) 0.10
- C) 0.15
- D) 0.20
Correct Answer: B) 0.10
Explanation
Number of moles = \( \frac{Number of atoms}{Avogadro number} \)
1 moles of water = \( 3 \times 10^{22} \)
2 moles of water = \( 3 \times 10^{22} \times 2 = 6 \times 10^{22} \)
Number of moles = \( \frac{6 \times 10^{22}}{6 \times 10^{23}} \) = 0.10
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