A motor truck releases an average of 5.0g CO into air for every km covered....

CHEMISTRY
POST UTME OAU

A motor truck releases an average of 5.0g CO into air for every km covered. How many molecules of CO will be emitted into the air if the truck travels 8 km?[C = 12; O = 16; NA= 6.02 × 1023

  • A) 4.32
  • B) 2.48
  • C) 8.6
  • D) 6.82

Correct Answer: C) 8.6

Explanation

First, let's find out the total amount of CO emitted by the truck after traveling 8 km. Since the truck releases 5.0g of CO for every km, we can calculate the total amount of CO released as follows:

\(Total\,CO\,emitted = 5.0g/km \times 8km = 40g\)

Now, to find the number of CO molecules released, we need to determine the number of moles of CO. The molar mass of CO is calculated by adding the atomic masses of carbon (C) and oxygen (O):

\(Molar\,mass\,of\,CO = C + O = 12 + 16 = 28g/mol\)

Next, we can find the number of moles of CO released:

\(Moles\,of\,CO = \frac{Total\,CO\,emitted}{Molar\,mass\,of\,CO} = \frac{40g}{28g/mol} = 1.43\,mol\)

Finally, we can calculate the number of CO molecules released by multiplying the number of moles by Avogadro's number (N\(_A\) = 6.02



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