If \(x^2+y^2+-2x-6y+5 =0\), evaluate dy/dx when x=3 and y=2.
FURTHER MATHEMATICS
WAEC 2022
If \(x^2+y^2+-2x-6y+5 =0\), evaluate dy/dx when x=3 and y=2.
- A. 2
- B. -2
- C. -4
- D. 4
Correct Answer: A. 2
Explanation
\(x^2+y^2+-2x-6y+5 =0\)
When differentiated:
\(x^2+y^2+-2x-6y+5 =0\) → 2x + 2y - 2 - 6 = 0
where x=3 and y=2
2[3] + 2[2] - 8 = 0
6 + 4 - 8 = 2
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