A solid rectangular block has a base that measures 3x cm by 2x cm. The...

FURTHER MATHEMATICS
WAEC 2022

A solid rectangular block has a base that measures 3x cm by 2x cm. The height of the block is ycm and its volume is 72cm\(^3\).

i. Express y in terms of x.

ii. An expression for the total surface area of the block in terms of x only;

iii. the value of x for which the total surface area has a stationary value.

Explanation

volume of rectangular block(cuboid) = l × b × h

V = 3x × 2x × y

72 = 6x\(^2\)y

y = \(\frac{72}{6x^2}\)

y = \(\frac{12}{x^2}\)

ii.

Area of cuboid = 2(lb + lh + bh)

l = 3x, b = 2x, h = y

A = 2(3x(2x) + 3x(y) + 2x(y))

A = 2(6x\(^2\) + 3xy + 2xy)

A = 12x\(^2\) + 6xy + 4xy

A = 12x\(^2\) + 10xy

where y = \(\frac{12}{x^2}\)

A = 12x\(^2\) + \(\frac{120}{x}\)

iii.

At stationary point \(\frac{dy}{dx}\) = 0

\(\frac{dA}{dx} = 2(12x^2-1) + -120x^{-1-1}\)

24x - 120x\(^{-2}\)

\(\frac{dA}{dx}\) = 0

24x- \(\frac{120}{x^2}\) = 0

multiply through by x\(^2\)

24x\(^3\) - 120 = 0

24x\(^3\) = 120

x\(^3\) = 5

x = ?5

x = 1.71



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