Solve (\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)
FURTHER MATHEMATICS
WAEC 2021
Solve (\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)
- A. \(\frac{7}{5}\)
- B. \(\frac{6}{7}\)
- C. \(\frac{-7}{6}\)
- D. \(\frac{-6}{7}\)
Correct Answer: B. \(\frac{6}{7}\)
Explanation
(\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)
3\(^{-2(x + 2)}\) = 3\(^{5(x - 2)}\);
-2(x+2) = 5(x - 2)
-2x -4 = 5x - 10
-7x = -6
x = \(\frac{6}{7}\)
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