The essays of 10 candidates were ranked by three examiners as shown in the table.

Explanation

Rank coefficient = I = \(\frac{6\sum d^2}{n(n^2 - 1)}\)

= 1 - \(\frac{6(141)}{10(10^2 - 1)}\)

= 1 - \(\frac{6(141)}{10 \times 99}\)

= 1 - \(\frac{846}{990}\)

= 1 - 0.85

= 0.15

(ii)

Rank coefficient = 1 - \(\frac{6(78)}{10(10^2 - 1)}\)

= 1 - \(\frac{468}{990}\)

= 1 - 0.472

= 0.53

(iii)

Rank coefficient = 1 - \(\frac{6(78)}{10(10^2 - 1)}\)

= 0.53

(b) Examiner II and III