A particle starts from rest and moves in a straight line such that its velocity,...
FURTHER MATHEMATICS
WAEC 2019
A particle starts from rest and moves in a straight line such that its velocity, V ms\(^{-1}\), at time t second is given by V = 3t\(^2\) - 6t. Calculate the acceleration in the 3rd second.
- A. 0 ms\(^{-2}\)
- B. 3 ms\(^{-2}\)
- C. 6 ms\(^{-2}\)
- D. 9 ms\(^{-2}\)
Correct Answer: C. 6 ms\(^{-2}\)
Explanation
V = 3t\(^2\) - 6t
\(\frac{dx}{dt}\) = 6r - 6
at t = 4
\(\frac{dx}{dt}\) = 6 x 4 - 6 = 24 - 6
= 18
at t = 3
\(\frac{dy}{dt}\) = 6 x 4 - 6
= 24 - 6
= 18
at t = 3
\(\frac{dx}{dt}\) = 6 x 3 - 6 = 18 - 6
= 12
\(\frac{dy}{dt}\) = 18 - 12
= 6ms\(^{-2}\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *