Three forces N, 14N and 16N acting on a particle keep it in equilibrium. Find...

FURTHER MATHEMATICS
WAEC 2019

Three forces N, 14N and 16N acting on a particle keep it in equilibrium. Find the angle between the forces 10N and 16N.

Explanation

If we let \(\beta\) be the angle between the forces 10N and 16N,

then \(\beta\) = (180\(^o\) - \(\theta\))

Applying the cosine rule; cos\(\theta\) = \(\frac{10^2 + 16^2 - 14^2}{2 \times 10 \times 16}\) = 0.5

If \(\theta\) = cos\(^{-1}\)(0.5) = 60\(^o\)

\(\beta\) = 180\(^o\) - 60\(^o\) = 120\(^o\)



Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *
Add Math
Don't want to keep filling in name and email whenever you make a contribution? Register or login to make contributing easier.