If P = \({n^{2} + 1: n = 0,2,3}\) and Q = \({n + 1:
FURTHER MATHEMATICS
WAEC 2017
If P = \({n^{2} + 1: n = 0,2,3}\) and Q = \({n + 1: n = 2,3,5}\), find P\(\cap\) Q.
- A. {5, 10}
- B. {4, 6}
- C. {1, 3}
- D. { }
Correct Answer: D. { }
Explanation
\(P = {n^{2} + 1: n = 0,2,3} \therefore P = {1, 5,10}\)
\(Q = {n + 1: n = 2,3,5} \therefore Q = {3, 4, 6}\)
\(P \cap Q = { }\)
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