Given n = 3, evaluate \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!}\)
FURTHER MATHEMATICS
WAEC 2016
Given n = 3, evaluate \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!}\)
- A. \(12\)
- B. \(2\frac{1}{2}\)
- C. \(2\)
- D. \(\frac{11}{24}\)
Correct Answer: D. \(\frac{11}{24}\)
Explanation
n = 3, \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!} = \frac{1}{(3-1)!} - \frac{1}{(3+1)!}\)
= \(\frac{1}{2} - \frac{1}{24} = \frac{12 -1}{24}\)
= \(\frac{11}{24}\)
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